If tan² θ = 1 – e², then the value of sec θ + tan³ θ × cosec θ is

If tan² θ = 1 – e², then the value of sec θ + tan³ θ × cosec θ is

A

2 – e²

B

(2 – e²)1/2

C

(2 – e²)²

D

(2 – e²)3/2

Answer:

The correct option is D. (2 – e²)3/2

Note