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Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on dissolving 1 gof Y in 20 g of liquid X. If molar mass of X is 200, what is the molar mass of Y?

Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on dissolving 1 gof Y in 20 g of liquid X. If molar mass of X is 200, what is the molar mass of Y?

A
20
B
50
C
100
D
200
Answer:

The correct option is B. 50

Note

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